Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of Alexander Doyle (born 1841)

1881 England, Wales & Scotland Census in Bootle, Cumberland, England

Alexander Doyle and 7 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

Alexander Doyle's household

Male

Alexander

Doyle

Head
Female

Sarah

Doyle

Wife
Female

Susannah

Doyle

Daughter
Male

William

Doyle

Son
Female

Margaret

Doyle

Daughter
Female

Sarah

Doyle

Daughter
Male

Andrew

Doyle

Son
Female

Winifred

Doyle

Daughter
First name(s) Alexander
Last name Doyle
Relationship Head
Marital status Married
Age 40
Birth year 1841
Birth place Ireland

Household members (8 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

Alexander

Doyle

Head

Married

40

1841

Ireland

Sarah

Doyle

Wife

Married

37

1844

Frizington, Cumberland, England

Susannah

Doyle

Daughter

Single

15

1866

Frizington, Cumberland, England

William

Doyle

Son

Single

13

1868

Frizington, Cumberland, England

Margaret

Doyle

Daughter

Single

11

1870

Millom, Cumberland, England

Sarah

Doyle

Daughter

Single

9

1872

Millom, Cumberland, England

Andrew

Doyle

Son

Single

6

1875

Millom, Cumberland, England

Winifred

Doyle

Daughter

Single

2

1879

Millom, Cumberland, England

Explore Findmypast's newspaper collections

Explore the 1881 Census and millions of historical records for free with Findmypast. Find out more about the household of Alexander Doyle in Bootle in 1881, and follow the Doyle family through time in other national records, newspapers and more.

We've found family trees for Alexander Doyle

We’ve found Alexander Doyle in 26 family trees. Find out more about Alexander Doyle's household and view the Doyle family in family trees created by Findmypast members.

Not who you're looking for?